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1+0.8x-5x^2=0
a = -5; b = 0.8; c = +1;
Δ = b2-4ac
Δ = 0.82-4·(-5)·1
Δ = 20.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{20.64}}{2*-5}=\frac{-0.8-\sqrt{20.64}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{20.64}}{2*-5}=\frac{-0.8+\sqrt{20.64}}{-10} $
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